If z = x + iy, then show that
where bϵR, representing z in the complex plane is a circle.
Given z = x + iy
⇒ z̅ = x – iy
Now, z z̅ + 2 (z + z̅) + b = 0
⇒ (x + iy) (x – iy) + 2 (x + iy + x – iy) + b = 0
⇒ x2 + y2 + 4x + b = 0
This is the equation of a circle.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


