The complex number z which satisfies the condition
lies on
Given ![]()
Let z = x + yi
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⇒ |x + (y + 1) i| = |-x – (y – 1) i|
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⇒ x2 + (y + 1)2 = x2 + (y – 1)2
⇒ (y + 1)2 = (y – 1)2
⇒ y2 + 2y + 1 = y2 – 2y + 1
⇒ 2y = -2y
⇒ 4y = 0
⇒ y = 0 (x – axis)
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