If z = x + iy lies in the third quadrant, the
also lies in the third quadrant if
Since z = x + iy lies in the third quadrant, we get
X < 0 and y < 0
Now ![]()
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Since
also lies in third quadrant, we get
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⇒ x2 – y2 < 0 and -2xy < 0
⇒ x2 < y2 and xy > 0
But x, y < 0
∴ y < x < 0
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