Q34 of 66 Page 91

Where does z lie, if

Explanation:


Given


⇒ |z – 5i| = |z + 5i|


⇒ |x + iy – 5i| = |x + iy + 5i|


⇒ |x + i (y – 5) |2 = |x + i (y + 5) |2


⇒ x2 + (y – 5)2 = x2 + (y + 5)2


⇒ 20y = 0


⇒ y = 0


∴ z lies on the x – axis.


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