Fill in the blanks of the following
If
then the locus of z is ………….
Explanation:
Given ![]()
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⇒ 6 |x – 2 + iy| = π |x + 2 + iy|
Squaring on both sides,
⇒ 36 |x – 2 + iy|2 = π2 |x + 2 + iy|2
⇒ 36 [x2 – 4x + 4 + y2] = π2 [x2 – 4x + 4 + y2]
⇒ (36 – π2) x2 + (36 – π2) y2 – (144 + 4π2) x + 144 – 4π2 = 0
Which is a circle.
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