Eight chairs are numbered 1 to 8. Two women and 3 men wish to occupy one chair each. First the women choose the chairs from amongst the chairs 1 to 4 and then men select from the remaining chairs. Find the total number of possible arrangements.
Formula:-
nPr ![]()
Given: -
W1 can take chairs marked 1 to 4 in 4 different way.

W2 can 3 chairs from marked 1 to 4 in 3 different ways.
So, total no of ways in which women can take seat
4P2![]()
![]()
4P2
=12
There will be 6 chairs remains

M1 take seat in any of the 6 chairs in 6 different ways,
M2 can take seat in any of the remaining 5 chairs in 5 different ways
M3 can take seat in any of the remaining 4 chairs in 4 different ways.
So, total no of ways in which men can take seat
6P3![]()
=120
Hence total number of ways in which men and women can be seated
4P2x6P3![]()
=1440
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