Q1 of 64 Page 122

Eight chairs are numbered 1 to 8. Two women and 3 men wish to occupy one chair each. First the women choose the chairs from amongst the chairs 1 to 4 and then men select from the remaining chairs. Find the total number of possible arrangements.

Formula:-


nPr


Given: -


W1 can take chairs marked 1 to 4 in 4 different way.



W2 can 3 chairs from marked 1 to 4 in 3 different ways.


So, total no of ways in which women can take seat


4P2



4P2


=12


There will be 6 chairs remains



M1 take seat in any of the 6 chairs in 6 different ways,


M2 can take seat in any of the remaining 5 chairs in 5 different ways


M3 can take seat in any of the remaining 4 chairs in 4 different ways.


So, total no of ways in which men can take seat


6P3


=120


Hence total number of ways in which men and women can be seated


4P2x6P3


=1440


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