The number of ways in which we can choose a committee from four men and six women so that the committee includes at least two men and exactly twice as many women as men is
Formula:- (i)nCr=![]()
Given:-
Number of women=6,number of men =4
Group I should of 2 men and 4 women=4C2.6C4
GROUP II should of 3 men and 6 women=4C3.6C6
Required committee=4C2.6C4+4C3.6C6
=90+4
=94
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