Find the number of positive integers greater than 6000 and less than 7000 which are divisible by 5, provided that no digit is to be repeated.
(i)Thousand Place is to be fill with 6. Number of way =1
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Unit place can be fill either 0 or 5. Number of way=2

Hundred place can be fill with remaining 8 digits. Number of way =8

ten place can be fill with 7 digits. Number of ways= 7.
Thus, required number will be
=1 x 8 x 7 x 2
=112
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