A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected from the lot.
Formula: -(i)nCr![]()
Given: -Number of black ball =5,Number of red ball =6
Number of ways of selection of 2 black balls
=5C2![]()
Number of ways of selection of 3 red balls
=5C3![]()
Number of ways of selection of 2 black & 3 red ball
=5C2x5C3
=10×20
=200
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