There are 10 persons named P1,P2,P3, ... P10. Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements. [Hint: Required number of arrangement =7C4× 5!]
Formula:- (i)nCr![]()
Given:- there are 10 person named P1, P2, P3, ... P10.
Number of ways of P1 arrangement =5! =120
Number of ways arrangement of other
7C4![]()
Therefore, required number of arrangement = ![]()
=35 x 120
=4200
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