Q12 of 64 Page 122

There are 10 persons named P1,P2,P3, ... P10. Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements. [Hint: Required number of arrangement =7C4× 5!]

Formula:- (i)nCr


Given:- there are 10 person named P1, P2, P3, ... P10.


Number of ways of P1 arrangement =5! =120


Number of ways arrangement of other


7C4


Therefore, required number of arrangement =


=35 x 120


=4200


More from this chapter

All 64 →