A box contains two white, three black and four red balls. In how many ways can three balls be drawn from the box , if atleast one black ball is to be included in the draw.
[Hint: Required number of ways =3C1×6C2+3C2x 6C1+3C3.]
FORMULA:- (i)nCr![]()
Number of ways drawing at least one black ball =
=( 1 black and 2 other )or( 2 black and 1 other )or (3 black)
3C1x6C2+3C2x6C1+3C3
=3×15+3×6+1
= 45 + 18 + 1
= 64
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