Given: ![]()
First, we calculate
and then find its conjugate
Now, rationalizing
![]()
…(i)
Now, we know that,
(a + b)(a – b) = (a2 – b2)
So, eq. (i) become
![]()
![]()
[∵ i2 = -1]
![]()
![]()
![]()
Hence, ![]()
So, a conjugate of
is ![]()
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