Find the modulus of each of the following:

Given: ![]()
Firstly, we calculate
and then find its modulus
[∵ (a + b)2 = a2 + b2 + 2ab]
[∵ i2 = -1]
![]()
Now, we rationalize the above by multiplying and divide by the conjugate of 4 + 3i
![]()
…(i)
Now, we know that,
(a + b)(a – b) = (a2 – b2)
So, eq. (i) become
![]()
![]()
[∵ i2 = -1]
[∵ i2 = -1]
![]()
![]()
Now, we have to find the modulus of ![]()
So, ![]()


![]()
![]()
Hence, the modulus of
is ![]()
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