If
= x + iy, find x and y.
Consider,
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Now, rationalizing
![]()

In denominator, we use the identity
(a – b)(a + b) = a2 – b2



![]()
= (i)93 – (-i)3
= (i)92+1 – [-(i)3]
= [(i)92(i)] – [-(i2 × i)]
= [(i4)23(i)] – [- (-i)]
= [(1)23(i)] – i
= i - i
x + iy = 0
∴ x = 0 and y = 0
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