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5. Complex Numbers and Quadratic Equations
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Q16 of 202 Page 171

Show that for all n N.

To show:

Taking LHS,



[rationalize]



[∵ i2 = -1]


= (1 – i)n(1 + i)n


= [(1 – i)(1 + i)]n


= [(1)2 – (i)2]n [(a + b)(a – b) = a2 – b2]


= (1 – i2)n


= [1 – (-1)]n[∵ i2 = -1]


= (2)n


= 2n


= RHS


Hence Proved


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Questions · 202
5. Complex Numbers and Quadratic Equations
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