If z1 is a complex number other than –1 such that |z1| = 1 and z2 =
then show that z2 is purely imaginary.
Let z1 = a + ib such that | z1| = √(a2 + b2) = 1
Now, ![]()
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Thus, the real part of z2 is 0 and z2 is purely imaginary.
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