If P(A) = 0.3, P(B) = 0.6, P(B/A) = 0.5, find ![]()
Given, P(A)=0.3,P(B)=0.6,P(![]()
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=0.5 X 0.3
=0.15
P(A∪B)=P(A)+P(B)-P(A∩B)
=0.3+0.6-0.15
=0.75
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