Mark the correct alternative in each of the following:
If
and
then ![]()
→ (Given)
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= 1 – P(A⋃B) → (1)
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= 1 – [P(A) – P (A⋂B)] → (2)
Now,
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P(A⋂B) = P(B)
1/2
P(A⋂B) ![]()
→ (3)
According to the addition theorem of probability,
P(A⋃B) = P(A) + P(B) – P(A⋂B)
→ From (3) and (Given)
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→ (4)
Now using Equation (1) and (2)
P (A⋃B) + P(
) = 1 – P(A⋃B) + 1 – [P(A) – P (A⋂B)]
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