Q36 of 249 Page 31

Mark the correct alternative in each of the following:

If P(A) = 0.4, P(B) = 0.8 and P(B/A) = 0.6, then P(A ∪ B) =


P(A) =0.4 , P =0.6 , P(B) = 0.8 → (Given)


P =0.6



P(A⋂B) = P(A) 0.6


P(A⋂B) = 0.4 0.6


P(A⋂B) = 0.24 → (1)


Now, according to the addition theorem of probability,


P(A⋃B) = P(A) + P(B) – P(A⋂B)


= 0.4 + 0.8 – 0.24 → From (1)


= 1.2 - 0.24


= 0.96

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