Mark the correct alternative in each of the following:
If A and B are such that
and
then ![]()
P(A∪B) =
, P
=
→ (Given)
Now,
P
= P(A∩B) → (1)
P(A∩B) = 1 - P(A∩B)
→ From (Given) & (1)
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Also,
P
= 1 – P(A) → (2)
P
= 1 – P(B) → (3)
Now, according to the addition theorem of probability:
P(A⋃B) = P(A) + P(B) – P(A⋂B)
![]()
![]()
→ From (2) & (3)
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