Mark the correct alternative in each of the following:
If a, b, c are in G.P. and ![]()
, then xyz are in
Given: a,b,c are in GP
Let us assume
⇒ ![]()
⇒ ![]()
As a,b,c, are in GP
b2 =ac
⇒ k2y =kx.kz
=kx+z
⇒ 2y = x+z
∴ x,y,z are in AP
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