Let the five terms be a1, a2, a3, a4, a5.
And,
A = 16, B![]()
Now, these 5 terms are between A and B.
∴ A, a1, a2, a3, a4, a5, B.
Now all of them are in GP
So we now have 7 terms in GP with the first term being 16 and seventh being 1/4.
∴ Tn = arn–1
Here Tn
, a = 16 and
⇒ ![]()
⇒ ![]()
⇒ ![]()
∴ a1 = Ar = ![]()
a2 = Ar2 = ![]()
a3 = Ar3 = ![]()
a4 = Ar4 = ![]()
a5 = Ar5 = ![]()
∴ The six GM between 16 and 1/4 are
.
Couldn't generate an explanation.
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