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20. Geometric Progressions
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Q4 of 176 Page 20

Find the sum of the following series :

5 + 55 + 555 + … to n terms.

Taking 5 in common we get


5(1 + 11 + 111 + ....n)


Now Multiply and Divide by 9 we get


⇒ )


⇒ )


⇒


⇒


Now First term is in GP.


10, 100, 1000…to n terms


∴ Common Ratio = r =


∴ Sum of GP for n terms = …(1)


⇒ a = 10, r = 10, n = n


∴ Substituting the above values in (1) we get


⇒


⇒


For the second term the summation is n.


∴


⇒ .


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Questions · 176
20. Geometric Progressions
1 2 3 3 3 3 3 3 4 5 6 6 6 6 7 8 9 10 11 12 13 14 15 16 17 1 2 3 4 5 6 7 8 9 1 1 1 1 1 2 2 2 2 2 2 2 2 2 3 3 3 4 4 4 4 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 1 1 1 1 1 2 3 4 5 6 7 8 8 8 8 9 10 11 12 13 1 2 3 4 5 6 7 8 8 8 8 8 9 9 9 10 10 10 11 11 11 11 12 13 14 15 16 17 18 19 20 21 22 23 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
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