Find the sum of the following series :
9 + 99 + 999 + … to n terms.
Taking 9 in common we get
9(1 + 11 + 111 + ....n)
Now Multiply and Divide by 9 we get,
⇒
)
⇒
)
⇒ ![]()
⇒ ![]()
Now first term is in GP.
10, 100, 1000…to n terms
∴ Common Ratio = r = ![]()
∴ Sum of GP for n terms =
…(1)
⇒ a = 10, r = 10, n = n
∴ Substituting the above values in (1) we get
⇒ ![]()
⇒ ![]()
For the second term the summation is n.
∴ ![]()
⇒
.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.