Find the sum of the following series :
0.5 + 0.55 + 0.555 + …. to n terms
Let
S = 0.5 + 0.55 + 0.555 + .....n terms
Taking 5 as common we get,
S = 5(0.1 + 0.11 + 0.111 + ...nterms)
Multiply and divide by 9
⇒
)
⇒
)
⇒ ![]()
⇒ ![]()
Now 1 + 1 + 1 + ..n = n
For 0.1 + 0.01 + 0.001 + ..nterms
∴ Common Ratio = r = ![]()
∴ Sum of GP for n terms =
…(1)
⇒ a = 0.1, r =
, n = n
∴ Substituting the above values in (1) we get
⇒ 
⇒ ![]()
For second term the summation is n.
∴ ![]()
⇒ ![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

