How many terms of the G.P.
are needed to give the sum
?
Given:
Sum of GP ![]()
∴ Common Ratio = r ![]()
a = 3
To find: Number of terms = n.
Sum of GP for n terms = ![]()
⇒ 
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
∴ n = 10.
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