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20. Geometric Progressions
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Q11 of 176 Page 20

The 4th and 7th terms of a G.P. are and respectively. Find the sum of n terms of the G.P.

Nth term of GP is Tn = arn - 1


⇒ …(1)


Nth term of GP is Tn = arn - 1


⇒ …(2)


Divide (1) by (2)


⇒


⇒


⇒


Substituting in 1 we get


a = 1


Sum of GP for n terms =


a = 1, r = , n = n.


⇒


⇒


⇒


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The ratio of the sum of the first three terms is to that of the first 6 terms of a G.P. is 125 : 152. Find the common ratio.

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Questions · 176
20. Geometric Progressions
1 2 3 3 3 3 3 3 4 5 6 6 6 6 7 8 9 10 11 12 13 14 15 16 17 1 2 3 4 5 6 7 8 9 1 1 1 1 1 2 2 2 2 2 2 2 2 2 3 3 3 4 4 4 4 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 1 1 1 1 1 2 3 4 5 6 7 8 8 8 8 9 10 11 12 13 1 2 3 4 5 6 7 8 8 8 8 8 9 9 9 10 10 10 11 11 11 11 12 13 14 15 16 17 18 19 20 21 22 23 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
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