Let's measure the length of the sides of the following triangles and let's compare the measurement of the angles.

(i) The given triangle is as shown below:

Given PQ=2.5cm, QR=3.5cm, PR=4cm

To find the ∠P is greater than which angle.

In the given ΔPQR,

∠P is opposite to side QR,

And from the given values, side QR=3.5cm is greater than side PQ=2.5cm

Now from the given figure, ∠R is opposite to the side PQ.

⇒ QR>PQ

We know in a triangle the shortest side is always opposite the smallest interior angle and the longest side is always opposite the largest interior angle.

⇒ ∠P>∠R

Hence ∠P is greater than ∠R.

(ii) The given triangle is as shown below:

Given XY=4cm, YZ=5cm, XZ=6cm

To find the ∠x is greater than which angle.

In the given ΔXYZ,

∠X is opposite to side YZ,

And from the given values, side YZ=5cm is greater than side XY=4cm

Now from the given figure, ∠Z is opposite to the side XY.

⇒ YZ>XY

We know in a triangle the shortest side is always opposite the smallest interior angle and the longest side is always opposite the largest interior angle.

⇒ ∠X>∠Z

Hence ∠X is greater than ∠Z.

(iii) The given triangle is as shown below:

Given AB=4cm, BC=5cm, CA=3cm

To find the ∠C is greater than which angle.

In the given ΔABC,

∠C is opposite to side AB,

And from the given values, side AB=4cm is greater than side AC=3cm

Now from the given figure, ∠B is opposite to the side AC.

⇒ AB>AC

We know in a triangle the shortest side is always opposite the smallest interior angle and the longest side is always opposite the largest interior angle.

⇒ ∠C>∠B

Hence ∠C is greater than ∠B.