Q1 of 39 Page 150

Let’s write the value of x in each of the following figure.


The given figure is as shown below:



Given PQT = 55°, RST = 60°


To find the angle, i.e., TRS = x°


Now in the given figure PQ is parallel to TS, so


PQT = RTS as they form is alternate interior angles.


So RTS = 55°….(i)


Now consider ΔRTS,


We know in a triangle the sum of all three interior angles is equal to 180°.


So in this case,


RTS + TRS + RST = 180°


Substituting the values from given criteria and equation(i), we get


55° + TRS + 60° = 180°


TRS = 180° - 60° - 55°


TRS = 65°


So the measurement of unknown angle in the given figure is 65°.


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