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27. Specific Heat Capacities of Gases
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Q4 of 65 Page 77

Consider the processes A and B shown in figure. It is possible that


From the graph, we can see that the slope of process B is steeper than that of process A.


Now in an isothermal process, under constant temperature, Pressure(P) x Volume(V) = constant … (i) (according to Boyle’s law)


Differentiating on both sides:


PdV + VdP = 0.


slope = = … (ii)


For an adiabatic process,


PVᵞ = constant


Where,


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