Solve the following systems of equations:
⇒ 2x + 4y = 3 …(i)
⇒ 4x + 2y = 3 …(ii)
Multiplying eq2 by 2 and subtracting from eq1
2x + 4y – 8x – 4y = 3 – 6
⇒ -6x = - 3
⇒ x = 1/2
Thus, 2 × 1/2 + 4y = 3 ⇒ y = 1/2
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