Q38 of 266 Page 3

Solve the following systems of equations:






Adding eq 1 and eq2


⇒ 2(x + z) = 6


⇒ x = 3 – z


(3) – (2) – (1)


⇒ y – 5z = - 4


⇒ y = -4 + 5z


Substituting in eq2


⇒ 3 – z - 4 + 5z + z = 2


⇒ 5z = 3


⇒ z = 3/5


Thus, x = 3 – z


⇒ x = 12/5


Y = 5z – 4


⇒ y = -1


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