Q8 of 266 Page 4

A two-digit number is 4 times the sum of its digits. If 18 is added to the number, the digits are reversed. Find the number.

Let the one’s digit be ‘a’ and ten’s digit be ‘b’

Given, number is 4 times the sum of its digits.

10b + a = 4(a + b)

⇒ a = 2b -----(1)

Also, if 18 is added to the number, the digits are reversed.

⇒ 10b + a + 18 = 10a + b

⇒ a – b = 2 ----- (2)

Substituting a from eq1 in eq2

⇒ b = 2

Thus, a = 4

Number is 24

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