Q32 of 266 Page 3

Solve the following systems of equations:




Equating both equations


⇒ 6u – 2v = 2u + 6v


⇒ u = 2v


Substituting value of u


⇒ 2(6v – v) = 5 × 2v × v


⇒ v = 1


Thus, 2(3u – 1) = 5u


⇒ 6u – 2 = 5u


⇒ u = 2


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