Solve the following systems of equations:

Multiplying eq2 by 2 and adding to eq1

⇒ 2/(3x + y) = 3/4 - 2/8

⇒ 3x + y = 4 ---- (3)

Multiplying eq2 by 2 and subtracting from eq1

⇒ 2/(3x – y ) = 1

⇒ 3x – y = 2 ----- (4)

Adding (3) and (4)

⇒ 6x = 6

⇒ x = 1

Thus, y = 3 – 2 = 1