Q37 of 266 Page 3

Solve the following systems of equations:






Subtracting eq2 and eq3


⇒ x + 3y = 0


⇒ x = -3y


Substituting in eq1


⇒ -3y – y + z = 4


⇒ z = 4 + 4y


Substituting in eq2


⇒ -3y – 2y + 12 + 12y = 1


⇒ 7y = -11


⇒ y = -11/7


Thus, x = 33/7


And z = 4 – 44/7 = - 16/7


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