The sum of two numbers is 8. If their sum is four times their difference, find the number.
Let the numbers be ‘a’ and ‘b’.
Given, sum of two numbers is 8. If their sum is four times their difference, find the number.
⇒ a + b = 8 ------ (1)
Also,
a + b = 4(a – b)
⇒ a + b = 4a – 4b
⇒ a = 5b/3
Substituting value of a in eq1
⇒ 5b/3 + b = 8
⇒ 8b/3 = 8
⇒ b = 3
Thus, a = 5
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