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9. Arithmetic Progressions
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Q15 of 202 Page 9

Find the second term and nth term of an A.P. whose 6th term is 12 and the 8th term is 22.

a6= a + 5d

12= a + 5d …(i)


a8= a + 7d


22= a + 7d …(ii)


Subtracting (i) from (ii), we get,


10= 2d


d= 5


from (i)


12 = a + 5(5)


12= a + 25


a= -13


a2= a +d


=-13 +5


=-8


an= a + (n-1)d


= -13 + (n-1)5


=-18 +5n


More from this chapter

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13

Find the 12th term from the end of the following arithmetic progressions:

(i)


(ii)


(iii)

14

The 4th term of an A.P. is three times the first and the 7th term exceeds twice the third term by 1. Find the first term and the common difference.

16

How many numbers of two digit are divisible by 3?

17

An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively, find 32nd term.

Questions · 202
9. Arithmetic Progressions
1 2 3 1 2 3 4 5 6 7 8 9 10 11 12 1 2 2 2 2 2 3 3 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 1 2 3 4 5 6 7 8 1 2 3 4 5 5 5 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42
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