If the first term of an A.P. is a and nth term is b, then its common difference is
‘a’ is the first term of the A.P,
‘b’ is the (n)th term and ‘d’ is the common difference of the A.P.
Then, we have b = a + (n–1) d
= a + (n + 1)d
Hence, ‘d’ = ![]()
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