Find the sum of first 25 terms of an A.P. whose nth term is given by
.
Given, nth term, an = 2 – 3n
Put n = 1, a1 = 2 – 3(1) = -1
Put n = 25, a15= 2 – 3(15) = -43
Therefore, S25 =
(-1 – 43)
=
(-44) = -925
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