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9. Arithmetic Progressions
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Q47 of 202 Page 9

If the 5th term of an A.P. is 31 and 25th term is 140 more than the 5th term, find the A.P.

a5=31

a +4d =31 (i)


a25= 140 + a5


a + 24d= 140 + 31


31 -4d +24d=171 [ from (i) ]


20d=140


d=7


Putting the value of d in (i)


a= 31 – 4(7) = 3


a1 = a=3


a2 =a +d=3 +7=10


a3 =a +2d=3 + 2(7) =17


Hence, the A.P. is 3, 10, 17,…


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45

Find where 0 (zero) is a term of the A.P.

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Find the middle term of the A.P..

1

The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceeds these term by 6, find three terms.

2

Three numbers are in A.P. If the sum of these numbers be 27 and the product 648, find the numbers.

Questions · 202
9. Arithmetic Progressions
1 2 3 1 2 3 4 5 6 7 8 9 10 11 12 1 2 2 2 2 2 3 3 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 1 2 3 4 5 6 7 8 1 2 3 4 5 5 5 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42
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