If the seventh term of an A.P. is 1/9 and its ninth term is1/7, find its (63)rd term.
a7=![]()
a +6d=
(i)
a9 =![]()
a +8d=
(ii)
subtracting (i) from (ii), we get,
2d=![]()
d=![]()
a=
– ![]()
=![]()
a63= a + 62d
=
+ ![]()
=1
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