The length of a string between a kite and a point on the ground is 90 metres. If the string makes an angle
with the ground level such that tan
=15/8, how high is the kite? Assume that there is no slack in the string.
Let the height of string = h (m)
Tan θ =
(given)
Sin θ = ![]()
In ∆ABC,
Sin θ = ![]()

= ![]()
17h = 90×15
h =
⇒ 79.41 m.
Therefore length of string = 79.41 m.
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