A fire in a building B is reported on teleported on telephone to two fire stations P and Q, 20 km apart from each other on a straight road. P observes that the fire is at an angle of 60° to the road and Q observes that it is at an angle of 45° to the road. Which station should send its team and how much will this team have to travel?
Let the distance between P and foot of building is
(
)
In ∆PRS
tan 60° = ![]()
√3 = ![]()
h = √3
---------(1)
In ∆QRS
tan 45° = ![]()
tan 45° = ![]()
1 = ![]()
h = 20+
---------(2)
on substituting value of h from eqn. (2) in eqn. (1)

20+
= √3![]()
√3
–
= 20
![]()
On rationalsing above fraction we get,
⇒
⇒ 10(√3+1)
= 10(1.732+1)
![]()
![]()
Therefore Station P has to send team. And distance between station P and
Building is 27.32 m.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.