Q1 of 107 Page 12

The height of a tower is 10 m. What is the length of its shadow when Sun’s altitude is 45°?


Let BC be the height of tower which is 10m


Sun`s altitude is 45°


Let AB would be the shadow of the tower x meters


∴ tan 45° = BC /AB (tan θ = perdendicular/base)


⇒ 1= 10/x


x= 10m


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