Q4 of 107 Page 12

From a point on the ground, 20 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is 60°, what is the height of the tower?

Let the height of the tower be AC = x m


Distance from the foot of the vertical tower = 20m


tan 60° = AC/ BC


√3 = x / 20 ( tan 60° = √3)


x = 20√3


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