If the angles of elevation of a tower from two points distant a and (a > b) from its foot and in the same straight line from it are 30° and 60°, then the height of the tower is

Given BC = a and BD = b
Let the height AB = h
In right ΔABD,
tan θ = ![]()
tan 30° = ![]()
![]()
……………1
In Δ ABC
tan 60° = ![]()
√3 a = h………………2
Multiplying 1 and 2
h2 =
b × √ 3 a
h = √ab
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