From a point on a bridge across a river the angles of depression of the banks on opposite side of the river are 30° and 45° respectively. If bridge is at the height of 30m from the banks, find the width of the river.
Let A and B be the points on the bank n opposite sides f the river and BC be the width of the river.
BC = BD+DC ⇒ (
m.
AD be the height of the bridge.
In ∆ADC
tan 45° = ![]()
1![]()
---------(1)
In ∆ADB
tan 30° = ![]()
![]()
------------(2)

Width of the river = ( ![]()
⇒ 30√3+30
⇒ 30(√3+1)m.
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