A tower subtends an angle α at a point A in the plane of its base and the angle of depression of the foot of the tower at a point b metres just above A is β. Prove that the height of the tower is b tan α cot β.
In the fig let CD is the height of tower

CD = a + b
In ∆ABD
Cot β = ![]()
Cot β = ![]()
x = b Cot β ………………(1)
In ∆ADC
tan α = ![]()
tan α = ![]()
⇒ CD = b Cot β tan α
Therefore height of the tower is b Cot β tan α
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