Q41 of 97 Page 187

In the adjoining figure, AC>AB and AD is the bisector of ∠A. show that ∠ADC>∠ADB.

Given: AC>AB and ∠BAD = ∠DAC


To prove: ∠ADC>∠ADB


Proof:


Since AC > AB


∠ABC > ∠ACB


Adding ∠A on both sides


∠ABC + ∠A > ∠ACB + ∠A


∠ABC + ∠BAD > ∠ACB + ∠DAC … As AD is a bisector of ∠A


∴ ∠ADC > ∠ADB


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